Quote:
Originally Posted by paulunderwood
The tests for (L+2)^(n+1)==5 (mod n, L^2+1) will take another 3 to 4 weeks

Sorry for my ignorance but n is the Wagstaff PRP right, but what is L ? and what is meant by "n, L^2 +1" in the modular expression? My guess is that (L+2)^(n+1)==5 for both (mod n) and (mod L^2+1) ?
(and yes I did spend a bit of time looking for an answer myself, before I get told to study myself :) But not too much since it is not
that important)